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e C=0 group normally shows up around 1715 cm for ketones. the case of the molecule below, the V for the CEO group is less tha

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Answer #1

Here in this structure the carbonyl group is in resonance with the double bond.

By conjugating the carbonyl, the C=O bond is weakened, which shifts the IR peak down. You can think of it in terms of, if there is little or no conjugation, the electrons are firmly based in the C=O bond. As soon as we introduce some resonance structure, or conjugation, now those electrons can delocalise over 3-4 atoms or even more. This weakens the C=O bond, moving the IR peak down to lower wavenumbers.

So the stretching frequency decrease from 1725 to 1700.

(Resonance Structure)

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