Question

Constants Whet is he magnitude of the electric field at point A. 5.00 cm from te t face of the left-hand sheet? Express your answer to three significant figures and include the appropriate units Two very lange, nonconducting plaeic sheets, each 10.0 cm thick, as shown in the following fure Figure 1). These surfoce charpe era . 2.20 prC/㎡ , and 혀-4.00 pC/m2. Use Gauss's law to find the magnitude and dredtion of the electric field at the folowing points far from the edges of these sheets E-I Value Units Part What is the roction of the electie field at poit A. 5.00 cm from e lut face of the let-hand sheef? ○ uowards. Figure 1 of1 O downwards PartC Wh at is magnitude of oloene fekl齻point B, 1.25 em to" ǐner surta00 of the right-hand sheet? Express your answer to three significat figures and include the appropriate units 0 cm 12 em 10 cm R-Value Units

Answer 1

Answer :

For this equation you want to use Gause's Law in One Dimension: E = σ/2ε0. The σ = σ1 + σ2 + σ3...+ σn.

So for

a) you add all of the σ's together.  

so the answer to a) is (σ1 + σ2 + σ3 + σ4)/2ε0 = 4.2*10^-6/2ε0 N/C = 2.1*10^-6/ε0 N/C

b) dirction is to the left

for c) you find the difference between the σ on either side of point b [(σ1 + σ2)-(σ3 + σ4)]/2ε0

= -8.2*10^-6/2ε0 N/C = -4.1*10^-6/ε0 N/C

d) direction is to the left

for e ) you do the same as you did for c