Question

Many hot-water heating systems have a reservoir tank connected directly to the pipeline, so as to allow for expansion when the water becomes hot. The heating system of a house has 79.6 m of copper pipe whose inside radius is 7.93 x 10^{- 3} m. When the water and pipe are heated from 23.9 to 71.6 °C, what must be the minimum volume of the reservoir tank to hold the overflow of water?

Answer 1

Hence required volume is,

1.17*10^-4 m^3

olu9i ๆ ๆ then find is Av. So, then amount I then amount of increase in the volume of the pipe due to the increase of temp. is a VP, So, A Vo = Và B2 AT then amount of increase in the volume of the water due to the incrase of temp.is, DVw, A Vw = Vo Bw AJ then Avis, AU = A VW-AVA so AV, Here is 2 Dupa Vo BC AT AV = Voß wAT-Voß AT I AUw = Voßw AT ) So, Voat is common, then, Du= VoDT (Bw - Bc ) so, put values, Bw = 20 7X15%*, BC = SIX100C AU = (35*(7.93x16%)*79.0)*(71-6-23-3)<(207x 106– Sixto) Au= (0.015718) *(7.44 x 163) 1-4 m3 Hence reavired volume is I 1.178 184 m3. Av=10178154 m3) Hence require I hope help you!!