Question

What is the magnitude, E, of the net electric field at P? Express your answers using two significant figures. Constants | Periodic Table View Available Hint(s) Two point charges Qi--q and Q2 = +31 are located at the origin and (-31,0), respectively. A point P is located at a distance of I directly below Q1 Assume that q-4.1 nC and l-1.10 cm. [Take k-1/(4TEo)-9.00 x 10 N m2/C2] N/C Submit Request Answer Part B what is the direction, 8 of the net electric field at P? Express your answer as positive angle using two significant figures 酾鋸

Answer 1

E_1 = kQ_1/l^2 = -9 times 10^9 times 4.1 times 10^-9/(1.1 times 10^-2)^2 (-y^^) E_1^vector -= 30.49 times 10^4 y^^N/C E_2 = kQ_2/squareroot (3l)^2 + l^2 = 4 times 10^9 times 3 times 4.1 times 10^-9/(squareroot 10)^2 times (1.1)^2 times 10^-4(-1/squareroot 10 y^^+ 3/squareroot 10x^^) E_2^vector = 9.14 (-1/squareroot 10 y^^+ 3/squareroot 10 x^^) times 10^4 E_2^vector = (-2.890 y^6 8.670 x^^) + 10^4 Net electric field(E) = E_1^vector + E_2^vector = (8.670 x^^+ 27.6 y^^) times 10^4 N/C magnitude of net E = squareroot (8.67)^2 + (27.6)^2 + 27.6 y^^) times 10^4 N/c Magnitude of net E = squareroot (8.67)^2 + (27.6)^2 times 10^4 N/C = 28.929 times 10^4 N/C Angle theta = tan^-1(27.6/8.67) = 72.56 degree