Question

1. A equilibrium constant of 1e24 means that: (Check all that apply, wrong answers will be deducted from the score.)

   a.

   At equilibrium, the vast majority of the molecules present are the reactants.

   b.

   At equilibrium, the vast majority of the molecules present are the products.

   c.

   There are slightly more reactants than products in the solution at equilibrium.

   d.

   There are slightly more products than reactants in the solution at equilibrium.

   e.

   It is likely that the reaction will occur very quickly.

   f.

   It is likely that the reaction will occur very slowly.

2. A equilibrium constant of 1e-24 means that: (Check all that apply, wrong answers will be deducted from the score.)

   a.

   At equilibrium, the vast majority of the molecules present are the reactants.

   b.

   At equilibrium, the vast majority of the molecules present are the products.

   c.

   There are slightly more reactants than products in the solution at equilibrium.

   d.

   There are slightly more products than reactants in the solution at equilibrium.

   e.

   It is likely that the reaction will occur very quickly.

   f.

   It is likely that the reaction will occur very slowly.

Answer 1

Equilibrium constant gives the information about direction of the reaction.

Rp Key = 1x 103 or Ixe] R=Reactant P= Product @ At. Eน14 bum & Forward Reaction is - favoured y Equilibrium Concentration 6 Key - 103 103 or e3 e3 1 [P]e ~ [R]. At equilibrium" © keq <10-3 or e-3 - → At Equilibrium → Backward Reaction is - favoured 01 Key = 1XE24 - [P]. >>[R] - forward Reaction takes place . → fast forward Reaction correct is (b) At Equilibrium the vast majority of the molecules present are the products les It is likely that the reaction will occur a very quickly 011 Keq = 1x 2-24 -> [P]e <<[RIC, Backward Reaction is favoured slow forward Reaction Correct! @ At Equilibrium the vast majority of the molecules - present are the reactant 0 It is likely that the reaction will occur - very slowly