Question

1. What is the predominate product for the following dehydration reactions (draw or name): a) 2-methyl-1propanol -->(H2SO4, 140C) b) 2-methyl-1propanol -->(H2SO4, 180C) c) 1-butanol --->(H2SO4, 140C) d) 1-butanol --->(H2SO4, 180C)
can you the give the names?

Answer 1

Dear Student, Kindly refer to the complete solution. Feel free to ask if you face difficulty in understanding any part of the solution attached so that we can assist you in a better way.

Dear Student, in presence of HSO4, dehydration of alcohols takes place to form alkenes or ethers. At 180°C, alkene is produced At 140°c, peimary alcohos produce ethers. ( 2-methyl-1-peopanse (1650, 140°c) Lih (feom 1454) at 140°c Loe to al lether) Diisobutyl ether w 2-methyl-1-propand (hsoy, at 180°C) or J-Ho t a ( 11 carbocation د پر۔ مل at 180'c P.ZO.

| 2 hybride shift Ho Chh (more stable Bºcolbocation de Calkene) Isobutylene (i) 1-butanol (145, 140°c) ze-chynerg-eh-oh at 1400c 30-che-het-oh C-CH-CH-Chor 1400 the-he-er-eh- eh-th-chert A C-th-oh-oh- o h-oh- (ethel) Dibutyl ether P.FO

(iv) 1-butanol (4soy, 180 c) +36-c-cth Chh Oh H at 180°C A C-CH2=CH-Chor the-eh-eh-eh Cipearbocation) 1 1,2 hydride to shift. Be-ch-CH-CH (more stable -HO Carbocation) & A C-ch-eH=eth (minor) BC-CH=CH-Cth (mole substituted alkene & more stable) (major) (But-2-ene) Best wishes!!