Question

Given the unbalanced equation, Or(NO3)3 Caq)+LiOH Caq)., Li Noglaq) + Crcoth how many grams og Cr(OH), are produced from 1.159 g Cr(NOx), (s) The percent yeild for a given reaction is 51.%. If the theoretical amount is predicted to be 5.229. what was the actual yeild for the reaction ? The reachon between iron (I)oxide and aluminum, to produce aluminum Oxide and iron, has a heat oy reachon COH) equal to - 851.5 kJ/mole How much energy is released in kJ)ig 0.77 moles oy aluminum are consumed ? D. The reaction between nitrogen and oxygen gases requires the absorption g 43 kJoy energy per moll og nitrogen according to the following Chemical equation, Nalg) + O2(g) → 2ND (9). How many grams of No are produced the reaction 1 353 KJ of heat are absorbed by the reaction? OM worn 20 bang OTH on t he blog

Answer 1

This question is solved as follows:

Soli We are given, No C (NO₂)₂ (aq) + 2OH(aq) (aq) + tiot LINO Cay) + Ca(OH) het us balance the son fintly 3 h NO, (aq) + C(OH ) (3) 3 (aq) + 3 hi OH (aq) of C (NO3). Nasked for the grams of GloHs , produced from 1.15 gn {as these both species are smole; so can be directly compared. 3 Colecular cut of Ca(NO3) = 51.9961 + (14 + 16 83) 3 = 51.9961 + 186 = 237.9961 u 23:996 " 6.022 x = 1 gm 1023 ama 7 amn 6.022x1023 you 237.996 I amee 237.9961 6.022 x 1023 - 39.52 x 10-23 Similarly, Molecular cat. of CCOH) = 51.9961+ (16+ 13 51.9961 + 51 = 102.9961 . 6.022 x 1023 anu & 1 gm i. I am = - 6.022 x 10² 27 102.99 6 1 ama = To 2.9961 6.02241073 9m - 17.1033 x 10-239m

Now we can represent that i C (NO₂) Cag) + 3 heOH(aq) t=0 39.52x 10-2 m 3 Le NO₂ (aq) + (046) to 3x(17 10 33x10-3gm " 39,52 x 10-23 gm of Cr(NO3)₂ gives = 3 X 17. 1035 X 10 gm & 1 gm of Cr (NO3)2 gives = 3X1 7 10 33 x 10 39.52 x 10-25 1. 15 gm of G (NO3)3 gives = 1.15 x 3 x 14.10 334 39.52 - 1.4 9 3 qm