Question

& Draw your two products (each in the most stable chair conformation) below using the numbering provided. Show only the -OH and tert-butyl groups on the ring. a) label each group as equatorial (eq) or axial (ax). b) label each group as top face (top) or bottom face (bot). OH (ax, top) (ax, bot) .OH (Eq, top 7 (Er, top cis-4-tert-butylcyclohexanol trans-4-tert-butylcyclohexanol 9. When looking at the two compounds prepared in this reduction, which compound is more stable, cis or frans Circle your answer. 10) Draw the most stable chair conformation shown below. Be sure to draw the substituents on the correct face of the molecule. 11) Complete the following reduction reactions by providing the products or starting material NaBH (then dil. acid quench H2O/ 0) NaBHA (then dil acid quench HO/H30+)

sodium borohydide reduction of 4 tert butylcyclohexanone. need help confirming top answers are correct and help with lower section. thanks

Answer 1

* cis-4- test - buty) cyclo hexanol Trans- 4-test butylcyclohexanol Trans Isomer is more stable bulky test butyl and-ou are in equitorial position stable. att methyls are in equitorial. ۵ د میر د و ه# ار 0H هل . د حد دء وامن