Q21. According to photoelectric effect equation,
K.E.max = (h * c) * (1/ - 1/cutoff)
where
K.E.max = maximum kinetic energy of an electron
h = Planck's constant = 6.626 x 10-34 J.s
c = speed of light = 3.0 x 108 m/s
= wavelength of light = 400 nm = 400 x 10-9 m
cutoff = cutoff wavelength of metal = 450 nm = 450 x 10-9 m
substituting the values,
K.E.max = [(6.626 x 10-34 J.s) * (3.0 x 108 m/s)] * (1/400 x 10-9 m - 1/450 x 10-9 m)
K.E.max = [(6.626 x 10-34 J.s) * (3.0 x 108 m/s)] * (2.78 x 105 m-1)
K.E.max = 5.5 x 10-20 J
This is the maximum kinetic energy of an ejected electron.
K.E.max per mole electrons = (K.E.max for one electron) * (Avogadro's number)
K.E.max per mole electrons = (5.5 x 10-20 J/electron) * (6.022 x 1023 electrons/mol)
K.E.max per mole electrons = 33251.5 J/mol
K.E.max per mole electrons = 33.3 kJ/mol
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