Answer : 13 ; Kinetic Energy = 70 J
mass of object = 10kg
Final velocity of the body when it reaches at height 30m
distance travelled by bodu is 70 m or 0.7m
v^2 = u^2 - 2as = 0 - {2*(-10)*0.7} = 14
So velocity just as it reaches the ground = (Square root of 14) m/s
Kinetic energy = 1/2*m*v^2 = 1/2*10*14 = 70 J
Answer :15
KE = PE
1/2mv2 = 1/2kx2
mv2 = kx2
v2 = kx2/m
v2 = 100 x 0.252/50
v2 = 0.125
v2 = 0.354 m/s
Answer :16
momentum is conserved
m1u1 +m2u2 = m1v1 +m2v2
(10x 5) + ( 2 x 0) = (10 x v1 ) + ( 2 x 8.3)
10v1 = 33.4
v1 = 3.34 m/s
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