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The electron in a hydrogen atom falls from an excited energy level to the ground state...

The electron in a hydrogen atom falls from an excited energy level to the ground state in two steps, causing the emission of photons with wavelengths of 1870 and 102.5 nm. What is the quantum number of the initial excited energy level from which the electron falls?

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Given The e Emission Emission of photons with wavelength 1870 and 10215 nm. The Hotel Energy Emitted during the transilom E =2:18 x 10-18 = 2.04681018 => 2118x1018 - 12.046x16 19 ] (02) => nz 2.18810-18 2.04681018 ne 1.0654 n= V1.0654 => n = 1.032/ [

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