Question

Determine the pH of the following solution:

0.852 M NH4NO3

Answer 1

1 03 - о: ЯК 2 м of alf Sol Given: WHY NO₂=0.80 NH4NO2 is a salto weak base (N₂) & Strong acid CHNO₃). it can hydrolye & acts as acid . pt should <7 - Ky of NH₃ = 1.8 x 10 = ta fs NHL, NO2 = 1014 ka = 5.56xiolo tiös 1.8x اب Pc | NHC Nok) - No Calt Hngrah Initial 0.852m Edu) 0.862x ka= [tNaz] [NA] INH NG]

0.852-X I since, 0.852 too small also small - so86x102 → 5.roxiolo x² =>x= [(p.exe x55.56x1610) = 2.1765x1ās og sex [Anoz} ~ [st]~ 2.1765x103 pH = -log[at] =55log (2:1768) FPH a 4.66 Acids No.982
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