Question

Item 19 19 of 21 For each of the follouing seactiors, calcalate AH ASand AGa 25 "C Sute whether or not the reactien is spontaneous the reaction is not spottaneous, would a change in tempecahare male ispontaniooa? so, should the mpaanue be rahed or lowered from 25 C Part A 2CH.()CHe)+He() Express your answer to one decimal place. AE ? AH Beauest Answr Submt Part B Calculate AS 25 C Expeess your answer so one decimal plece VAI J/K 126 21

Answer 1

2 CHA (9) ► C₂H6 (9) + H₂ (9) sexw = [H (546) + oH; (,)] – - [2 AH (CHA)Z = (-84.0 +0)-(2x(+416) AHORA= + 65.2 kJ ® sexw = ($C3H6) +5°43) – 25'(Chn) = (229.2 + 130-1)-(2 X 186.3) AG = AH - TAS T= 25+ 2+3 = 298 K AG = 6512 ks - 298k :*(- 12:42) 1692 168.98 kt AG >0 so REACTION is not spontaneous. AG° will NOT BECOME Asax= - 1207514] NEGATIVE EVEN IF Tempt RAURE is INCREASED