According to law of dilution MV = M'V'
Where M = Molarity of stock = 2.50M
V = Volume of the stock = 2.50L
M' = Molarity of dilute solution = 0.125M
V' = Volume of the dilute solution = ?
Plug the values we get
V'=(MV)/M'
=(2.50M*2.50L)/0.125M
= 50.0L
So volume of water added ,V"=V'-V
=50.0L-2.50L
= 47.5 L
=47.5L*10^3mL/L
=47.5*10^3 mL
Problem: How many milliliters of water should be added to yield a solution that has a...
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