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Problem: How many milliliters of water should be added to yield a solution that has a concentration of 0.125 given you starte
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Answer #1

According to law of dilution MV = M'V'
Where M = Molarity of stock = 2.50M
V = Volume of the stock = 2.50L

M' = Molarity of dilute solution = 0.125M
V' = Volume of the dilute solution = ?
Plug the values we get

V'=(MV)/M'

=(2.50M*2.50L)/0.125M

= 50.0L

So volume of water added ,V"=V'-V

=50.0L-2.50L

= 47.5 L

=47.5L*10^3mL/L

=47.5*10^3 mL

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