Question

3. Southeast Express is a regional, overnight, freight service. Customers can leave their parcels for shipping at drop-off bi
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Answer #1

Answer:

Mean = 604.55

Median = 600

Standard Deviation = 1368.35

Solution:

Calculation of Mean

S.No. Loss Size (X) No. of Losses (f) f*X
1 200 10 2000
2 600 8 4800
3 1000 2 2000
4 2000 1 2000
5 2500 1 2500
SUM 22 13300

Mean = Sum(f*X)/Sum(f) = 13300/22 = 604.55

Calculation of Median:

S.No. Loss Size (X) No. of Losses (f) Cumulative Frequency (cf)
1 200 10 10
2 600 8 18
3 1000 2 20
4 2000 1 21
5 2500 1 22

N is 22. Average of N/2 and N/2+1 is average of 11 and 12th value. From the CF values in the above table we can see that both the 11th and12th value lies in the category of loss size of 600.

Therefore 600 is the median.

Calculation of Standard Deviation:

Standard Deviation = [Sum {f*(X-Mean)^2}/N-1]^0.5

S.No. Loss Size (X) No. of Losses (f) X- Mean (X-Mean)^2 f*(X-Mean)^2
1 200 10 -404.55 163660.7025 1636607.025
2 600 8 -4.55 20.7025 165.62
3 1000 2 395.45 156380.7025 312761.405
4 2000 1 1395.45 1947280.703 1947280.703
5 2500 1 1895.45 3592730.703 3592730.703
Sum 7489545.455
Variance 1872386.364
Standard Deviation 1368.35
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