Answer:
Mean = 604.55
Median = 600
Standard Deviation = 1368.35
Solution:
Calculation of Mean
S.No. | Loss Size (X) | No. of Losses (f) | f*X |
1 | 200 | 10 | 2000 |
2 | 600 | 8 | 4800 |
3 | 1000 | 2 | 2000 |
4 | 2000 | 1 | 2000 |
5 | 2500 | 1 | 2500 |
SUM | 22 | 13300 |
Mean = Sum(f*X)/Sum(f) = 13300/22 = 604.55
Calculation of Median:
S.No. | Loss Size (X) | No. of Losses (f) | Cumulative Frequency (cf) |
1 | 200 | 10 | 10 |
2 | 600 | 8 | 18 |
3 | 1000 | 2 | 20 |
4 | 2000 | 1 | 21 |
5 | 2500 | 1 | 22 |
N is 22. Average of N/2 and N/2+1 is average of 11 and 12th value. From the CF values in the above table we can see that both the 11th and12th value lies in the category of loss size of 600.
Therefore 600 is the median.
Calculation of Standard Deviation:
Standard Deviation = [Sum {f*(X-Mean)^2}/N-1]^0.5
S.No. | Loss Size (X) | No. of Losses (f) | X- Mean | (X-Mean)^2 | f*(X-Mean)^2 |
1 | 200 | 10 | -404.55 | 163660.7025 | 1636607.025 |
2 | 600 | 8 | -4.55 | 20.7025 | 165.62 |
3 | 1000 | 2 | 395.45 | 156380.7025 | 312761.405 |
4 | 2000 | 1 | 1395.45 | 1947280.703 | 1947280.703 |
5 | 2500 | 1 | 1895.45 | 3592730.703 | 3592730.703 |
Sum | 7489545.455 | ||||
Variance | 1872386.364 | ||||
Standard Deviation | 1368.35 |
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