Question

Remember to show all work and/or reasoning, For the system shown at the right find the tension in the string and the acceleration. Draw the free- body diagrams for the hanging block and the cart. 890 g 450 g

Answer 1

Free body diagrams: Yel T - IN (Normal borce) M F = 4.4 N. mi 450 grams m / Mg sino me =4.4 M = 890 gramy Mgcaso 0 - 19° mg Where g = 9.8 m/s² is acceleration due to gravity a → Acceleration from the bree body diagram, we can write mg-T = ma or 0.450X9.8 – T = 0.450 a or 4.41- T = 0.45a And, - TF - mgsino = Ma T+ 4.4-0.890% 9.8 * Sin 19° = 0.890 a or or T+ 1.56 = 0.890 a

Adding equation (1) and (2), we get

                                   

1.34a = 5.97

                            or,    

a = 4.46 m/s2

Putting the value of 'a' in equation (1), we get

                                    

T = 2.4 N

Hence, the tension in the string is 2.4N and the acceleration of the block is 4.46 m/s².