Question

A 2.92−g peanut is burned in a bomb calorimeter containing 1,301 g of water. The temperature...

A 2.92−g peanut is burned in a bomb calorimeter containing 1,301 g of water. The temperature of the water increases from 20.09

°

C to 30.06

°

C. Calculate the energy released per gram of peanut. (The specific heat of water is 1.000 cal/g

·

°

C.)
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Answer #1

Given:

m = 1301 g

C = 4.184 J/g.oC

Ti = 20.09 oC

Tf = 30.06 oC

use:

Q = m*C*(Tf-Ti)

Q = 1301*4.184*(30.06-20.09)

Q = 54271 J

Now use:

Energy released per gram = Q / mass

= 54271 J / 2.92 g

= 18586 J/g

= 18.6 KJ/g

Answer: 18.6 KJ

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