A 2.92−g peanut is burned in a bomb calorimeter containing
1,301 g of water. The temperature of the water increases from 20.09
° C to 30.06° C. Calculate the energy released per gram of peanut. (The specific heat of water is 1.000 cal/g· ° C.) |
Given:
m = 1301 g
C = 4.184 J/g.oC
Ti = 20.09 oC
Tf = 30.06 oC
use:
Q = m*C*(Tf-Ti)
Q = 1301*4.184*(30.06-20.09)
Q = 54271 J
Now use:
Energy released per gram = Q / mass
= 54271 J / 2.92 g
= 18586 J/g
= 18.6 KJ/g
Answer: 18.6 KJ
A 2.92−g peanut is burned in a bomb calorimeter containing 1,301 g of water. The temperature...
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