Answer:
Step 1: Explanation:
q = nCΔT where, q = the heat absorbed or released from the substance
n = moles of the substance
C = the molar heat capacity of the substance
ΔT = the change in temperature of the substance
Step 2 : Calculation of moles of C4H6O2
We know,
moles= mass / molar mass = 300 g / 86.09 g/mol = 3.48 mol [ note: 1 kg = 1000 g so 0.30 kg = 300 g ]
Step 3: Calculation of C
ΔT = ( 53.1-39.2 ) ºC = 13.9 ºC = 13.9 K [ 13.9ºC temperature change is the same as a 13.9 K temperature change ]
q = 6.64 x 103 J
By using above equation
q = nCΔT
=> C = q / {n x ΔT}
on substituting the value
=> C = ( 6.64 x 103 J ) / { ( 3.48 mol ) x ( 13.9 K ) } = 1.4 x 102 J.mol-1.K-1
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