From the HNMR spectra we can see that there is a 6H signal which is a doublet, coupled with the 1C heptet, which means that we have a: -CH(CH3)2 portion in our molecule. The other high signal is a proton without any H neighbours which, judging by its position and by the high signals in the CNMR spectrum, is probably from an alkene carbon (supported by the signal right below 1500 cm-1 in the IR spectrum. The highest C signal in the CNMR spectrum is the second C in the double bond, which is probably bonded to to halogens (the strong signal around 870 cm-1 in the IR spectrum is also coherent with this). It is hard to determine which are the halogens, but the most normal would be chlorine, so my guess is that the structure is:
444 CHAPTER 9 NUCLEAR MAGNETIC RESONANCE AND MASS 5PLOTHOM C OMETRY Tools for Structure Determine CHAPTER...
PROBLEMS L 445 of the H the structure of the compound Hand C spectra to the structure you 10) that gives the followinTH place carbons with signals in the propose. Use letters to comp s ur I R ani e ( F 949-951). Asignal s in the H NMR spectrum, and FIGURE 9.49 The 'H NMR spectrum simulated for Problem 9.43. 214 214 8pm FIGURE 9.50 A simulated broadband proton-decoupled SC NMR spectrum for Problem 9.43 CH .CH 180 160...