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1. Titanium metal requires a photon with a minimum energy of 6.94 x 10- J to emit electrons. a. What is the minimum frequency
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Answer #1

la) E hv E -19 6.94 x/o I -34 6.634x 10 -1 1.04x10 1.0 4X101S C = A velecity f lys hiquiney A=wavelenyth Z x10 - 1 1.04 x 101Due to Lower en possible bejeet electrn is not 1. 2 10 9677 cm 2 2 l0967부( Cam -1 36 ( -1 1016구7( 243구2.66 -92yp57 cm em 36 -A =h a. -34 ゴS. 6.6メ/0 63 kg x 48 km/ha -3 4 Js メ 48メ0 3600 s 63 m - 34 -3 x 3600 s メ )o 6.6X10 丁s 63X48 k9- m -39- 3 23t60 Xm 24 1.15 X10 -34 6.6 X1O Ts ny x 3.4 Xl0 m/s 1.16 X10 -34+26-S 10 6.6 - 1-15 X 3.7 13 1.55 X10 4 m=-1, 0, 2S n: 2, lao,m0 2Sdy 770 dy3 dez (d) 2p n 2, -, m -, 0, t1 2Prs a My [Ne] 3s Valence electons 2, Unpaied elechos =o ) Ge [A] 3d 4s 4p Valemce electons=4, Unpaned elechons 2 10 (e) BA: Ar7

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