Question

Molecular Orbital Theory -- Diatomics -- Electron Configuration Using the molecular orbital model, identify the correct (valence) electron configurations for the following diatomic species. CN2 E02 CCN DCN+ BN2. A. (02)2(025*)2(12p)4 B. (02)2(02s*)2(n2p)4(02p)2(n2p*)1 c. (02)2(02s*)2(n2p)4(02p)2 D. (023)2(028*)?(12p)^(02p)1 E. (02)2(02s*)2(02p)2(n2p)^(n2p*)? F. (02)2(02s*)(02p)2(n2p)^(n2p*)4| G. (023)2(028*)2(02p)?(n2p3" (n2p*)3

Answer 1

The less Mio than diagram or equal -ozp for species with to 14 electrons is : (N2 , CN; Cnt) - - 2P s valence Shells TIP ze Map - 925 2S hround Shells as TIS configuration .. valence electronic for . { 14 eo is 125 125 Etap yester)" (020)

For species with total electrons greater than 14. o. (023 ) - Tże - energy 2P 2P - } Izp - UzP leuls valence 25 25 - T Grand luud TS is valence стране » , « < Sar < "Пzrта е -- ® N2 **** co 6:03 (0.% (Mar) coup 02 +8+01023() Cozp}(tzp)* Comp 3 ₃ 6+7 © Cozs;²(825 ? ( Hap de Cozp ja CN +1=14

CNT 6+7 > 12 elections, The ground shell has 4 electron] ... Remaining (12-4) ²8 electrons 1. are to be arranged in Mo for species <1400. Jers. - The * - 41 12p >(1T2) Coast CTTzps4 #ozs (023)? Answer ®. Has (2S)? N2 + 7+7+1 715 e-( exception) ® (25170254)? (72p)" (azp)? (temps