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Can someone explain what Im doing wrong? I did -(8.134)(235)ln(1.91X10^22) and got -98.06

Question 12 At a certain temperature, 235 K, Kp for the reaction, 4 NH3(g) + 5 O2 <=> 4 NO(g) + 6 H2O(g), is 1.91 x 1022. Cal

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Answer #1

AG ==RT enk where R= 8.314]/kmol = - 8.314x235* en (1.9181022) = -1953.79 51.304 = -100237J = - 100 KJ

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Can someone explain what Im doing wrong? I did -(8.134)(235)ln(1.91X10^22) and got -98.06 Question 12 At...
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