For destructive interference, the expression is as follows -
|L1-L2|= (n+1/2)λ
As mentioned in the problem, L1 = 8.0 m, L2 = 6.0 m
For second interference to be minimum -
Put, n=1
So, we have -
(1+1/2)λ= |8.0 - 6.0| m = 2.0 m
=> λ= (2 x 2) / 3 = 1.33 m
Therefore, the value of the frequency, f=v/λ
= 343.0 / 1.33 = 258.0 Hz (Answer)
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