Question

refer to photos

Determine the angle o so that the velocity of the car will be parallel to the slope when the car lands at the top of ramp B. ANS: b) The stunts driver felt that the set up in part (a) is too risky and decided to modify the set-up to one as shown in the figure below. He replaces ramp A with a horizontal elevation C at height H = 7.2 m above the ground and replaces ramp B with ramp D which has height h = 3.8 m above the ground and inclined at a = 25. (You can treat the car as a point object and ignore its length.) Elevation C Ramp D Determine w' and x' such that his car will land exactly on top of ramp D with velocity at an angle a, parallel to the ramp. ANS

can seem to start on part b!

Answer 1

21 trí the horizontal component or velocity remains unchanged , & it gains a vertically downward unward compor ment (o) when it reaches the incline plane. given that when it reaches the incline plane the velocity vecton is Res parallely down the plane. rence, tanda Now, we know that, the kinematic equation in vertical direction gives, bina 79(H-h) >> Vv = 129 CH-)

hence, u stana va vo cota » va Jag CH-h) cota it, t is the time tamen to reach the incline plane, then, (Hah) = 2 g +² >> to Johannes hence, as o't » n'a J2geH-i) cota. Jachtohy n = 2(Han) cota

vs (29 CH-4) cota 3) v' = 2*9.8*(7.2-3.8) Cot 25' mis = v= 17.50 6323 37 m/s - » v' = 17.5 mis (appron) & n'aa (Han) Cata x= ax (7.2-3.8) * Cotas' mis x = 14.582647 06 m/s l' = 14.58 m/s cappron) v=90

initially the vertical component of velocity is usino, up words. & it is displaced achow) & gravity is acting downward, so if tis the tine duration , then, -(Han) = usinot - t. gt² t - t 20 - #-) यू au sivat ausina 12 4./21H-h -2() = 2 usipo. + - + q) +- Levsima) t = 2094) = 0 a ta sering to the most achten º to video a segno)'s agentlig hence, ta visine + jag sina, & can't be negative

so, the horizontal distance n= (ucosa). 7 => x = vioso [v ] given, vaqo kr/hr »vo 90 x lovo mis - 3600 o va asmis = 30', g = 9.8 mis? Hah= (7.2-3.87 m = 3.4m So, no caso sin 3066530 7 (2560330) dessins) et 9.8 - 60.59858 336 m Ppron x = 60.6 my cappoon)