If someone could please explain where the (8.23-4.00) comes from I really dont understand that . Thanks!
It is example of expansion (PV) work, it is under constant external pressure (1 atm) , thus it is non-reversible work. We cannot use integrated equation that is applicable for reversible expansion.
Work done by system in Non-reversible expansion is given by ,
W = -Pex. *
, can be calculated by volumes at initial and final states.
W = - Pext.* (Vf - Vi)
Vf = Final volume after expansion
Vi = Initial volume before expansion
For this problem volume changes are represented in diagram and their values are indicated in diagram ( nothing else mentioned regarding volume, for this problem volumes are not calculated but already provided with : no need of any calculation).
So, V = (Vf - Vi) = (8.23 - 4.00 ) L
If someone could please explain where the (8.23-4.00) comes from I really dont understand that ....
Please answer all the blanks (volume if H2 and everything in analysis). TIA! Data 5 1 oong 0.00 10.5ml 2 o.olag 0.00 11.0 Trial 3 o.org 0.00 12.00 o Daag o.albg 0.00 10.0 ml 11.5ml Mass of Mg (g) Initial volume of Syringe (mL) Final volume of Syringe (mL) Volume of H (mL) Barometric pressure (torr) Ambient temperature (°C) Vapor pressure of H2O (torr) 779.314har 23. Oi 21.0 forr TA.314tar 23.0c 179.3 14ton 23.0¢ 779.314 ton 23.0c 779.31472 23.0c 21.0...