Question

- Part A A rectangular sample of a metal is 2.8 cmn wide and 690 um thick. When it carries a 43 A current and is placed in a 0.80 T magnetic field it produces a 6.1 kV Hall eml. Determine the following quantities: The Hall field in the conductor. Express your answer using two significant figures. Temples Symbols uido redo resēt keyboard shortcuts help 2.46.10-4 EH = Vim Submit Previous Answers Request Answer x Incorrect; Try Again; 2 attempts remaining - Part B The drift speed of the conduction electrons. Express your answer using two significant figures. Templates Symbols uido redoresbt keyboard shortcuts help W = m/s Submit Request Answer - Part C The density of free electrons in the metal. Express your answer using two significant figures. Temp@es Symbols uado redo reset keyboard shortcuts help electrons per m3

Answer 1

a)

the hall field can be found as

H = H_emf / d

where H_emf  is hall emf and d is width of sample

so,

H = 6.1e-6 / 0.028

H = 2.2e-4 V/m

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b)

the drift speed can be found as

v = H / B

where H is hall field and B is magnetic field

v = 2.178e-4 / 0.80

v = 2.7e-4 m/s

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c)

from the equation of drift speed in metals, the density of electrons (n) can be found as

n = I/ qvA

where q is charge, v is drift speed, A is area, I is current

n = 43 / 1.6e-19 * 2.723e-4 * 0.028 * 690e-6

n = 5.1e28 electrons / m³