Question

I need help solving this problem as well if I could get a step by step of how to solve it. Thank You

Refer to the data set and use the 30 screw lengths to construct a frequency dismbution. Begin with a lower class limit of 3 470 in, and use a class width of0 010 in The screws were labeled as having a length of 3 1/2 in El Click on icon to view the data Complete the frequency distribution below 0 Data Table 3 470 480)-3400 3479 3.508 3517 3508 3.483 3.497 3509 3.471 3505 3.504 3.504 3.496 3495 3.486 3494 3.502 3.479 3.506 3498 3498 3491 3.518 3502 3.506 3509 3.481 3.503 3.471 3503 3.492 de 3510-3 5203 (Type integers or decimals rounded to the nearest thousandth as needed.) Print Done

Answer 1

Steps to Create Frequency Distribution:

1) Width of the class is given to be 0.010.

2) Find the data range by subtracting the minimum data value from the maximum data value. In this case, the data range is 3.518-3.471 = 0.047

3) Find the desired number of groups by dividing the data range by class width. Ie 0.047/0.010 = 4.7. Ceiling of this value is 5 and we will create six groups each of 0.010 width starting from 3.47.

4) Then we count the no of data set in each interval and generate the frequency table.