Question

1. You are given a formula Lt where L is the length of the object, t is the elapsed time, and v is the object's velocity. You don't know what k represents. What are the SI units of k? 2. The surface area of a certain object is 2 square feet. What is the object's surface area in SI units? The only conversion factor you are allowed to use is 1 inch 2.54 cm

Answer 1

Here K^2 = L t/nu S.I. units of L is m, t is sec and v is m/sec so, k^2 = m s/m/sec = sec^2 So, k = sec uparrow S.I.unit of k is sec 2) S.A = 2(ft)^2 Now 1 ft = 12 inch [1 inch = 2.54 cm] 1 ft = 12 times 2.54 cm 1 ft = 30.48 cm 1 (ft)^2 = 929.03 cm^2 1 (ft)^2 = 929.03 times 10^- 4 m^2 Now [S.A. = 2 times 929.03 times 10^- 4 m^2 S.A. = 1858.06 times 10^- 4 m^2 S.A. = 0.18 m^2]