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Cd2+ forms two complexes with acetate, with the given overall formation constants. 1. Cd2+ (aq) + CH, COZ (aq) = Cd(CH,CO2)+

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Answer #1

1. Cd (CH3 cod Cdo + CH₃ CO2 ian) Cdrag + 2 CH₂ (0% (aa) - Cd (C13 CO2hland B2 = 1400 Cd (Cng Centen + CM, Chrom) = (a (C1, 6

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