Question

L JU" 10- 32) 32) A piece of iron (mass = 25.0 g) at 398 K is placed in a styrofoam coffee cup containing 250 mL of water at 298 K Assuming that no heat is lost to the cup or the surroundings, what will the final temperature of the water be? The specific heat capacity of iron = 0.449 gºC and water = 4.18 JgPC A) 287 K B) 388 K C) 348 K D) 325K E) 308 K

Answer 1

VB NM Answer : Given, mass of iron ani) = 25g. initial temperature of iron (Ti) = 398k. specific heat capacity of iron (as) = 0.44g 3/gcc. a mass of water from ) = 25g, (25me is equina initial temperature of_ 7;=2985 25g) water specific heat capacity of water (Cw) = 4:18 J/gc. valent to let the final temperature be It. Assuming that no heat is lost to the cup con) the surroundings I therefore heat lost by iron will be equal to heat gained by water il, - qm - qw. -(m, & cm x AT) = (2x Cw-DT) where, - qm= heat loss by iron. qw=heat gained by water DT = Tf - Ti m , m = mass of iron & water respectivas Cm, Cur= specific heat of iron & Water respe ofinely

-(m,&cm (IF- T;)) = (me & Cwx At-T;)) => -(@5g * 0.449 J/g*c» (TR - 393)) - (25g * 4:18 9/96- - 2338)) = -0.4ugtf & 178.702 K = 4.18 TF - 1245.64K. 4.629 If = 1424•342k. If = 307.7K ANSWER TAT 308k
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