Question

58 The rate for the tollowing ved LM NOU A Would be ng tachon at 300K was found approximate rate at 320k? N20449) 2002 (g) AZ A reaction occurs in three steps with the following rate O constants: KI=03MK2 0.05MkazySM. Step 1 Step 2 Step 3 (a) whion step is the slow step? Co) which step nas the lowest activehon herny

please help:)

Answer 1

For every 10 degree rise in temperature, rate of reaction becomes double. Here temperature rise is 20 degree. Therefore rate becomes 4 times.

Slowest step is that which have lowest rate constant .

Activation energy is lowest for that step which have maximum rate constant.

. At 300K Rate - 0.22 M No2 l min for every . reaction temperature 10°c rise in temperature, approximately becomes double rise is goe Therefore Here rate would be becomes 4 times. (Rate at 320k) ux ( Rate as 300k) - ux022 M No₂ / min = 0.88 M No2 min/ at Approximate rate 320k 1 K2:0 SM K₂=4.5M Step 3 Ak 0.3M Stepi - Step 2 Slowest It Step: is in that spep rate reaction (le Rate sequence which has lowest Constant) From above, Kz is lowest Step 2 is rate determining Therefore step. (6) Activation energy directly depends on the Rate constant. Lowest is the Rate constant Maximum is the activation energy and vice versa. Because K3 is highest. Therefore step 3 has Lowest activation energy.