question 3
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force due to 9uC
F1 = k q1 q / r^2
F1 = 9*10^9* 9* 3*10^-12/ 0.49^2 = 1.01 N
force due to - 9 uC
F2 = 9*10^9* 9*3*10^-12 / 0.49^2 = 1.01 N
since both the force acts at right angle, so net force is given by
F^2 = F1^2 + F2^2
F = 1.431 N
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Problem 2 : part (1) also needed.
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do comment in case any doubt, will reply for sure.. Goodluck
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