Question

QUESTION 1 6 points Save Answer The purpose of an indicator in an acid-base titration is to indicate the of the titration. Use Table 10.2 for the following question. If an acidic solution is titrated with a basic solution and methyl violet is used as an indicator, the solution color will change from to QUESTION 2 3 points Save Answer The molarity of a solution prepared by dissolving 17.0 g of hydrochloric acid (HCI (aq) in 133 mL of water is M (2 decimal place) 16.4 mL of 0.135 M NaOH is used to neutralize 46.9 mL of HCl. The concentration of the HCI м(3 solution is decimal places)

Answer 1

Question 1 the The is to indicate in acid-base titration peorpose of le pcorpose of an indicator [End point of the titration. If an acidic slation is titrated with a basic solution and methyl violet is used as an indicator, the solution colour will change from Lyellow to [Violet

Page 2 Question 2 Molarity of solution prepared by dissolving 17.0 gm f Hel in to water is to gim of Hel in 133 milf Explanation i IM Hd = Addition of 36.46 gem of Hel in 1 litre of water (Molar mass of Hd = 36-469/mole) 36.46 gins of Hel is equivalent to 30.67 ml of HCL (volume = Mass / Density) = 36.46/1619 = 30.67 m) Density of Hel = 1.19 g/ml percent concentration de most concentrated HCl = 37.5%. 30.67md of Hel = 30.67X 100/37,5 = 81.8 m2 Hence, to prepare I M HCl - Add 81.8mal of Hcl in 100omfwater continued in page

Page 3 II gims of Hd is equivalent to = 17/1.19 = 14.285ml Percent conc of most concentrated Hd is 37.5% 14.285 ml of Hel = 14.285 x 100 37.5 = 14.285 * 2.666 - 38.00ml IM 81.8ml 38.09 m – 1000ml - - 1000m - ? 38.0981 M of Hel 81.8 38.09ml - 133m1 = e = 0.465 M Hel = 123 x 0.465 1000 = 0.0618 MHU The Molarity of Solution prepared by dissolving 17.0 gm of Hel in 133ml of water is 1o. 06 M Hel ]

16. noh 0.135M NaOH is used to neutralise 46.9ml of Hel. the concentration of the Hel solution is Page 4 Answer:- Mivo = M2 V2 M = Molarity of Naot solution = 0.135M V = volume of NaOH solw 16.4ml used to neutralise Helsin = MIV = M2 V2 Mr = Molarity of Hel solution - ? Mr & MINI 4 = volume of Hd solution - 46.9ml = 0.135x16.4 46.9 The concentration of Hd solution is 0.047M = 0.047M