Question

A startled armadillo leaps upward (see the figure), rising 0.464 m in 0.220 s. What was its initial speed? What speed at this height? How much higher does it go?

Answer 1

a)

using wnd equation of motion

h = ut - 0.5*gt^2

0.464 = u* 0.22 - 0.5*9.8* 0.22^2

u = 3.187 m/s

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b)

v = u - gt

v = 3.187 - 9.8* 0.22

v = 1.03 m/s

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c)

v^2 = u^2 - 2g h

v = 0 at highest point

h = 3.187^2 / ( 2*9.8)

h = 0.518 m

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