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4) A company manufacturing solar panels wishes to test two new prototypes, A and B. The...

4) A company manufacturing solar panels wishes to test two new prototypes, A and B. The
panels are installed at 12 sites, and the average hourly energy outputs
are measured for both prototypes. The results of the measurements are summarized in the
following table,
Site 1 2 3 4 5 6 7 8 9 10 11 12
Prototype A 144.2 113.7 129.1 126.9 129.3 108.7 104.4 125.4 121.2 130.9 111.4 123.1
Prototype B 106.6 111.8 110.3 101.3 108.5 112.2 101.9 111.5 107.2 107.7 108.9 105.8
a) Can these two samples be treated as independent? Why or why not?
b) Construct a 95% confidence interval on the difference between the energy outputs.
c) Based on the result of part b), is there an indication that one prototype is better than the
other? If yes, which one?

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Answer:

4) A company manufacturing solar panels wishes to test two new prototypes, A and B. The
panels are installed at 12 sites, and the average hourly energy outputs
are measured for both prototypes. The results of the measurements are summarized in the
following table,
Site 1 2 3 4 5 6 7 8 9 10 11 12
Prototype A 144.2 113.7 129.1 126.9 129.3 108.7 104.4 125.4 121.2 130.9 111.4 123.1
Prototype B 106.6 111.8 110.3 101.3 108.5 112.2 101.9 111.5 107.2 107.7 108.9 105.8
a) Can these two samples be treated as independent? Why or why not?

The two samples be treated as dependent because the measurements are paired by site.

b) Construct a 95% confidence interval on the difference between the energy outputs.

Site

PrototypeA

PrototypeB

d=difference(A-B)

1

144.2

106.6

37.6

2

113.7

111.8

1.9

3

129.1

110.3

18.8

4

126.9

101.3

25.6

5

129.3

108.5

20.8

6

108.7

112.2

-3.5

7

104.4

101.9

2.5

8

125.4

111.5

13.9

9

121.2

107.2

14

10

130.9

107.7

23.2

11

111.4

108.9

2.5

12

123.1

105.8

17.3

CI = \bar d \pm t* \frac {s}{\sqrt{n}}

Confidence Interval Estimate for the Mean

Data

Sample Standard Deviation

11.9464

Sample Mean

14.55

Sample Size

12

Confidence Level

95%

Intermediate Calculations

Standard Error of the Mean

3.4486

Degrees of Freedom

11

t Value

2.2010

Interval Half Width

7.5904

Confidence Interval

Interval Lower Limit

6.9596

Interval Upper Limit

22.1404

95% CI for difference = (6.9596, 22.1404)

c) Based on the result of part b), is there an indication that one prototype is better than the
other? If yes, which one?

The 95% CI for difference (6.9596, 22.1404) does not contains 0 value. That is both upper and lower intervals are positive. We infer that the mean difference is significantly different from 0. Therefore we conclude that one prototype is better than the other.

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