Homework Answers
second order kinetics.
After 54 sec,
K2 = x/t*(a)*a0
k2 = ? M-1.sec-1
x = reacted concentration = 0.5-0.3 = 0.2 M
a0 = initial no of concentration of A = 0.5 M
a = concentration after time, t sec = 0.3 M
t = 54 sec
K2 = (0.5-0.3)/(54*(0.3)*(0.5))
K2 = 0.025 M-1.sec-1
after 171 sec,
After 54 sec,
K2 = x/t*(a)*a0
k2 = ? M-1.sec-1
x = reacted concentration = 0.5-0.16 M
a0 = initial no of concentration of A = 0.5 M
a = concentration after time, t sec = 0.16 M
t = 171 sec
K2 = (0.5-0.16)/(171*(0.16)*(0.5))
K2 = 0.025 M-1.sec-1
Hence, it is second order reaction , rate constant(K2) = 0.025 M-1.sec-1
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