Question

NO3 +I2 (in basic conditions) (e) IO3 NO2 C'o: I -1x2. X 6-1 X-6- X--0 X-1t6+S X-1+6 5 X-U 2. ro2+1e No u0 + le 3. anue 1UN 1UU0 e u u O3t u. GHr03I+ 5. 3+ro uN +40u03 6. 30H3H +roluNO- t 0 1uu 30H 0+2 1031UNO t luN03 +304- Mn t BrO (in acidic conditions) 0 luvo3 MnO

Can someone explain to me what Im doing wrong?

The correct answer is :

Answer 1

2. 210g mi 1. 2103 → Iz. > Iz + 6 H₂O (Balance outom; z + 12 ht -> Iz + 6H2O 1 (Balance Hatom) 4. 21037+ 12+*+10e → Io + 6H20 - 0 Charles 5. NO₂ + H2O → NO3 NO2 + H2O → NO] } t 24 * tel - 210 + 12ht + 10 NO₂ +10 H₂0 I2 + 6H₂O HONO3 + - 2007 2 10% +10 NO2 + 4H2O For basic condition : 8 on -> Iz + 10 No] + 8Ht 8on 2 IO 3 + 10 NO₂ + 4H₂O + 801 I2 + 10 NO3 + 8 H₂O 2 10 + 10002 +804 → Iz + 10 No] + 4H₂O