Question

It takes 51.0 J to raise the temperature of an 8.80 g piece of unknown metal from 13.0°C to 24.8°C what is the specific heat for the metal?

Answer 1

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Specific heat capacity is defined by the amount of heat required to raise the temperature of a 1 kg substance through 1^oC.

Given that, Total heat required to raise the temperature, $H=51\;J$

Change in temperature, $\Delta T=T_{2}-T_{1}=24.8^{o}C-13^{o}C=11.8^{o}C$

Mass of the substance, $m=8.80\;g=8.80\times10^{-3}\;kg$

(1 g = 10^-3 kg)

Therefore, Specific heat capacity of the metal is given by,

$C=\frac{H}{m\Delta T}=\frac{51\;J}{8.80\times10^{-3}\;kg\times11.8^{o}C}$

$\boldsymbol{\therefore C=491.14\;J/\left (kg^{o}C \right )}$

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