If you neglect the heat transferred to the calorimeter, the measure of specific heat will be given by the equatiom:
Specific heat = Heat transferred to water / (mass of Copper * temeprature change)
Since we have neglected the heat transferred to calorimeter, the numerator is lower than the actual Heat released meaning that the specific heat will be lower
Suppose you negleted to account for heat transferred to the caliorimeter. What percentage error would be...
When two objects are in thermal contact heat energy is transferred from the hot to the cold object until the temperature of both becomes equal (i.e., the objects are in thermal equilibrium). Suppose you pour 20-gram milk at 200C into a cup of 80-gram tea at 920C. Assume the specific heat of tea is 4.2 J/gram.0K and that of milk is 3.9 J/gram.0K Assuming no heat is lost into the surrounding air what is the temperature of the tea and...
Suppose that 288.0 J of heat is transferred by conduction from a heat reservoir at a temperature of 395.0 K to another reservoir. Calculate the entropy change if the temperature of the second reservoir is 100.0 K.
What would be the final temperature if 8.94 x 10^3 joules of heat were added to 454 grams of copper, specific heat 0.386 J/g0C, at 23.00C?
1) For part A, calculate q (the heat lost in calories) for copper and lead. The specific heats of these metals are in the background section. Then calculate q (the heat gained in calories) for the water in each case. Remember that you used 25.0 g of water in the experiment. Show your calculations 2)The heat lost by the metal and the heat gained by the water should be the same. Are they? If not, list possible sources of error....
When 54.5) of heat was transferred to 7.3 g of iron ore at 25.2°C, the temperature of iron ore increases to 56.2"C. What is the specific heat of the iron ore in C? Type your answer
What would have happened to a calculation of the specific heat of your metal in the second trial if you had not carefully dried the metal before reuse? Clearly explain your reasoning. NG 3 3. What would have been the effect on your calculation of the specific heat of the metal had you forgotten to add the correction for your calorimeter constant? Explain. 4. How would your data have been affected if you had failed to dry your calorimeter between...
How do I find the specific heat (experimental) and percent Error? The calorimeter is a styrofoam cup that weighs 19.9 g Aluminum Copper Iron Mass of Sample (g) 18.4 57.7 48.7 Mass of Calorimeter and cold water (g) 268.1 g 267.3 g 267.1 g Mass of Cold Water (g) 248.2 g 247.4 g 247.2 g Initial Temperature of Cold Water 16.6 °C 18 °C 18 °C Temperature of boiling water 100 °C 100 °C 100 °C Equillibrium Temperature 17 °C...
Question 5 Heat is to be transferred to Refrigerant 134a by flowing it through a long horizontal pipe at steady state. The pipe has an inner diameter of 5 cm. When refrigerant saturated vapour flows in at 20 kg/min and -6 °C, while exits at 800 kPa, the heat transfer rate to the refrigerant was found to be 3.5 kW. Assume an exit temperature in the range of 80 - 100°C and determine the percentage error between that assumed value...
Question 5 Heat is to be transferred to Refrigerant 134a by flowing it through a long horizontal pipe at steady state. The pipe has an inner diameter of 5 cm. When refrigerant saturated vapour flows in at 20 kg/min and -6 °C, while exits at 800 kPa, the heat transfer rate to the refrigerant was found to be 3.5 kW. Assume an exit temperature in the range of 80 - 100 °C and determine the percentage error between that assumed...
QUESTION 10 Suppose you start with 269g of ice at 0 °C. Calculate the amount of heat energy that must be transferred to convert the ice to steam at 100 °C. (Use 334kJ/kg for the latent heat of fusion 2.26x103kJ/kg for the latent heat of vaporization, and 4.19kJ/kg°C for the specific heat of water.) Note: use the unit k).