Question

Determine the average distance from Jupiter for the Europa moon using the third Kepler law. Use the distance of it and the given periods shown in the table. Compare your result with the one in the Table.

7. Determine la distancia promedio desde Júpiter para la luna Europa usando la tercera ley de Kepler. Use la distancia de lo y los períodos dados que se muestran en la tabla. Compare su (5 puntos) resultado con el de la Tabla TABLE 6-3 Principal Moons of Jupiter Problems 42,45,and ay Moon fo Europs 49 x 10 Mean distance Mass (kg) (Earth days) from Jupiter (km 9 10 1.7 4 x 10 671 x 10 1070 x 10 1883 x tos Ganymede 15 1016 Calisto 11167

Answer 1

As per kepler's 3rd law of planetary motion T^2 = [4pi^2/G M] R^3 (3.55 times 24 times 3600)^2 = (4 pi^2/6.67 times 10^-11 times 1.898 times 10^27) R^3 R = 6.709 times 10^5 km it is approx. same as given in the table.

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