Question

4. What is the trend with gravitational energy (Eg) from Position #2 to Position #4?

IN: Exploring Gravitational Potential Energy, Eg: ok 1 Tracking Energy of a Skydiver Landing on a Trampoline Thermal Energy of #2 Elastic Energy Kinetic Energy Gravitational Energy ox #3 Postion 1 Postoon 2 Position 3 Position 3 Position 4 Position 4 Position 5 of me #5 X distance stretched Ground 1. What do the different colors sections of the bars represent? It Show different encar 2. The law of conservation of energy states: energy cannot be created or destroyed, only transformed and transferred. Explain how the energy bars visually show this? 3. What forms of energy does the skydiver have at Position #3? 4. What is the trend with gravitational energy (E.) from Position #2 to Position #4? 5. What is the trend with kinetic energy (E) from Position #2 to Position #4? 6. What is the trend with thermal energy (Ehema) from Position #2 to Position #4?

5. What is the trend with kinetic energy (Ek) from Position #2 to Position #4?

6. What is the trend with thermal energy (Ethermal) from Position #2 to Position #4?

Answer 1

Assumptione : !. Skydriver started from set at position #I. Velocity at I = V, = Oms-'. 2. Datum for (xavitational Polential Energy for the sky drives + Earth system ů Choosen to be al ground , ie. GPE at #1'- 0 J. 3. Only intemal come ervative foru. acting on sky - drives is gravitational poole, acceleration = constant = - 19.8'ms-2) downwards. Solutions : 4 Gravitational Energy Eg , or Gravilational Potential Energy of Skydriver at postibn 2, Equus = + mg (75) =-(-mg ) (+78) -- (F 1(ax). - W . where , W = Work - done by internal conservative force. F : fosce (Mternal 'conservative force) = mg (d ) = -mg. oxo displacement wit ground = 42-XO5= 75-0=75 m. m = mass of sky-driver. 9 = 9.8 ms-'z ' accoleration due to gravity • → Eg (2) = mg (75). - mſc az). Similarly. Eg (4) 5 mg (25) - mg (24) H enue, Gravitation Energy is lineas wyt, height of sky-driver from ground

Solution Kinetic energy of sky-driver at position 12 , Ps obtained by: yang = Vovo + 2as. V2 = velocity at position #2 vi - Velocity at position #1. - 0 ms -1 = (assumed ). a = -9.8' - acceleration due to gravity. S: displacement : → Yas? - (0)2 + 21-9-8)( 185 75-100). Var? = 19.8 ( 25). Similarly. Via : 19.8 (75). K Brutic Energy at position #2 = Ek2i = 1 n V 23². Ekay = { m ( 14.8) (100-75) Ekiz) = mg (100 – 221) Similarly. Ek (4) = 1 m ( 19.8) (100-25) - mg (100 – 3,4)). Hence, trend of Kinetic Energy from position # 2 6 #4 also linear writ height of Isky-drives from ground . Ek = mg (iod – ): Solution : 6. Thermal Energy is is zero throughout the journey of sky-driver. as it is also evident from the bar-graph.
Motion under free fall that is under the influence of gravity only, the Gravitational Potential energy and Kinetic energy of an object shows linear trend. And the effect of thermal energy can be neglected as compared to above stated Mechanical energy.