Question

Two converging lenses are separated by 29.00 cm. The focal length of each lens is 9.000 cm. An object is placed 35.00 cm to the left of the lens that is on the left. Determine the final image distance relative to the lens on the right. Object Lens 1 Lens 2 Number 18.5 units cm the tolerance is +/-2% Click if you would like to Show Work for this question: Open Show Work

Answer 1

The thin lens equation is, 1 1 1 + f d d Here, d, is the object distance, d, is the image distance from the lens, and f is the focal length of the lens Solve the equation for the image distance d 1 1 1 do d f 1 1 1 f do do-f fao fd do-f O

For the first lens the image distance is, fido.1 do1-fi (9.0 cm)(35 cm) 35cm 9.0cm - 12.11cm The image formed by the first lens is 12.11cm to the right of first lens and the two lenses are separated by a distance of 29cm. So the object distance for the second lens is, 29 cm-12.11 cm do2 - 16.89 cm The image distance for the second lens is, fdo.2 d12 do2-f2 (9.0cm) (16.89 cm) 16.89 cm -(9.0cm - 19.26 cm Thus, the final image is at a distance 19.26 cm relative to the lens on the right