Moles of H2SO4 = molarity * volume ( in L )
= ( 43.0*10^-3)(in L)* 1.0
= 0.043
Heat released = moles of H2SO4 * neutralisation enthalpy
= 0.043 * 114
= 4.902 KJ or 4902 joules
Total volume = 70.0 + 43.0
= 113.0
Mass = volume * density
= 113 * 1.0
= 113 grams
Q = mass * specific heat * ∆T
4902 = 113 * 4.184 * ( Tf - 29.8 )
Tf= 40.17 °C
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