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A car starting from rest moves in a straight line with a constant acceleration of 1.70...

A car starting from rest moves in a straight line with a constant acceleration of 1.70 m/s² for 13.0 s, then slows down to a stop with a constant deceleration of 2.70 m/s². How far does it travel?

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Answer #1

Distance covered during acceleration phase

d = 1/2at2

d = 0.5*1.70*132

d = 143.65 m

also,

final velocity, v = at = 1.70*13 = 22.1 m/s

Distance covered during deceleration phase

02 - 22.12 = 2*(-2.70)d

d = 90.446 m

so,

total distance covered is 234.09 m

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