A car starting from rest moves in a straight line with a constant acceleration of 1.70 m/s² for 13.0 s, then slows down to a stop with a constant deceleration of 2.70 m/s². How far does it travel?
Distance covered during acceleration phase
d = 1/2at2
d = 0.5*1.70*132
d = 143.65 m
also,
final velocity, v = at = 1.70*13 = 22.1 m/s
Distance covered during deceleration phase
02 - 22.12 = 2*(-2.70)d
d = 90.446 m
so,
total distance covered is 234.09 m
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stotal in a straight line with a constant acceleration. At the
distance stotal the car has reached a speed of vfinal. Determine
how much time this took and the value of the constant acceleration.
Take stotal = 200 m and vfinal = 15 m/s.
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