part 1)
t = (xbar-µ)/(s/√n) = (0.50-0.50)/(0.06/√10) = 0.00
part 2)
Ho : p = 0.6
H1 : p ╪ 0.6
Level of Significance, α = 0.05
Number of Items of Interest, x = 35
Sample Size, n = 50
Sample Proportion , p̂ = x/n = 0.7
Standard Error , SE = √( p(1-p)/n ) =
0.06928
Z Test Statistic = Z = ( p̂-p)/SE =
1.4434
p-Value = 0.148914673
Conclusion: p value>α don't reject
null hypothesis
hence, there is no enough evidence to reject the claim at 0.05
significance level
Problem 6 Calculate the test statistic. (A z-score and a t-score are examples of test statistics.)...
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