Question

At a fixed temperature, equal moles of SO2 (g) and 02 (9) are mixed in a constant pressure container (the volume of the container changes in order to keep the pressure at a constant value). The SO2 (g) and O2 (g) are allowed to react, producing S03 (g): 2 SO2 (g) + O2 (g) → 2 S03 (9) If the initial volume of the container, before any reaction takes place, is 4.50 L, determine the volume of the container after the SO2 (g) and O2 (g) have reacted to completion. The final volume will be Submit Answer Tries 0/99

Answer 1

2502 + O₂ 2503 2 mole imole 2 mole initial xmot x mol mol mole Kieniting in / mole x mole reactant After reaction omole : Imole of O2 requir= 2 mole so2 ni z 1 1 1 - 2 2 1 " but sor it also x mole, so so, is in limiting condition. a mole of so, produce are mole SO3 2ae mole (remote so2 the moke O2) gasses have volume = 45 L hal moles 3x mole (a mole 503 + rmole 02) have volume = 45 x 3 x mat have volume = 28 mat i = 4.583 13.5 L u = 3.375 L Ansuler