The reaction is:
Na(s) + H2O(l) -> NaOH(aq) +H2(g)
Balance H:
Na(s) + 2 H2O(l) -> 2 NaOH(aq) +H2(g)
Balance Na:
2 Na(s) + 2 H2O(l) -> 2 NaOH(aq) +H2(g)
The equation is now balanced.
Oxidation state of Na is increasing from 0 in reactant to +1 in product.
So, Na is oxidised
Oxidation state of H is decreasing from +1 in reactant to 0 in product.
So, H is reduced
Answer:
2 Na(s) + 2 H2O(l) -> 2 NaOH(aq) +H2(g)
Na is oxidised
H is reduced
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