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12 + 1/4 = 14 + 14. The following forces are applied to a 15-kg bar (L = 0.6 m) that can rotate about its center. How much ti
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Answer #1

Torg4e is «efined .s T Peepen dicutar omponent of di st«nce from anis ce x Fcoo을 -6r는 5*들 19 12 x* 0 = 6. 6 85 Nm mi I5x lo.

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