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15. + -10.1 points 0/4 Submissions Used Calculate the standard enthalpy of formation of gaseous nitrogen monoxide (NO) using

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Answer #1

\DeltaH = 90.8 kJ

Explanation

Reaction 1 : N2 (g) + 3 H2 (g) \rightleftharpoons 2 NH3 (g) : \Delta H1 = -92.4 kJ

Reaction 2 : 4 NO (g) + 6 H2O (l) \rightleftharpoons 4 NH3 (g) + 5 O2 (g) : \Delta H2 = 1167.1 kJ

Reaction 3 : 2 H2O (l) \rightleftharpoons 2 H2 (g) + O2 (g) : \Delta H3 = 571.7 kJ

Desired reaction : 1/2 N2 (g) + 1/2 O2 (g) \rightleftharpoons NO (g)

Consider the operation : (2 * R1 - R2 + 3 * R3) / 4

This operation gives the desired reaction.

\DeltaH = (2 * \Delta H1 - \Delta H2 + 3 * \Delta H3) / 4

\DeltaH = [2 * (-92.4 kJ) - (1167.1 kJ) + 3 * (571.7 kJ)] / 4

\DeltaH = (-184.8 kJ - 1167.1 kJ + 1715.1 kJ) / 4

\DeltaH = (363.2 kJ) / 4

\DeltaH = 90.8 kJ

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