Question


For the reaction З КОН + Н, РО, - к, РО, +3Н,0 how many grams of potassium phosphate, K3PO4, are produced from 86.5 g of pota
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Answer #1

3 KOH + H3PO4 = K3PO4 + 3 H2O

Moles of KOH = mass / molar mass

= 86.5 / 56.1

= 1.542

Moles of K3PO4 = 1/3 * moles of KOH

= 1/3 * 1.542

= 0.514

Mass of K3PO4 = mole * molar mass

= 0.514 * 212

= 108.968 grams

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